268A - Games - CodeForces Solution


brute force *800

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Python Code:

c,d=[],[]

for i in range(int(input())):
    
    a,b=map(int,input().split())
    
    c.append(a)
    
    
    d.append(b)
    
    
cd=0
for i in range(len(d)):
    
    cd+=c.count(d[i])
print(cd)

C++ Code:

#include<bits/stdc++.h>

using namespace std;

int main() {
	int x;
	
	cin>>x;
	
	int h[x], g[x];
	for(int i = 0; i < x; i++) {
		cin>>h[i]>>g[i];
	}
	
	int count = 0;
	for(int i = 0; i < x; i++) {
		for(int j = 0; j < x; j++) {
			if(h[i] == g[j]) {
				count++;
			}
		}
	}
	cout<<count;
}


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